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Commit ec0807ab authored by patavirt's avatar patavirt
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......@@ -8,11 +8,12 @@ in the action formulation.
The action is
```math
S[Q] = \mathrm{Tr}[D(\hat{\nabla}Q)^2 + F_{ij}Q\hat{\nabla}_iQ\hat{\nabla}_jQ + \Omega Q]
S[Q] = \frac{i\pi\nu}{8} \mathrm{Tr}[D(\hat{\nabla}Q)^2 + \alpha F_{ij}Q\hat{\nabla}_iQ\hat{\nabla}_jQ + 4 i \Omega Q]
\,,
```
where $`\hat{\nabla}_j Q = \partial_j Q - i[\mathcal{A}_j, Q]`$. We'd
like the discretized functional to be also gauge invariant.
where $`\hat{\nabla}_j Q = \partial_j Q - i[\mathcal{A}_j, Q]`$
and $\Omega = \epsilon\tau_3 + i\Delta$, $\Delta^\dagger = \Delta$.
We'd like the discretized functional to be also gauge invariant.
We subdivide the space to cells, centered on a rectangular lattice
$`\vec{r}_j=(h j_x, h j_y, h j_z)`$ with $`j_{x,y,z}\in\mathbb{Z}`$
......@@ -49,7 +50,6 @@ the symmetry.
## Derivative term
We then discretize
%
```math
S_2
=
......@@ -78,19 +78,7 @@ U_{ji}
=
\sum_{n=0}^\infty i^n |\vec{r}_i-\vec{r}_j|^n \int_{-1/2}^{1/2}ds_1\int_{-1/2}^{s_1}ds_2\ldots\int_{-1/2}^{s_{n-1}}ds_n\, \mathcal{A}(s_1)\cdots\mathcal{A}(s_n)
```
```math
U_{ji}
\approx
1 + i h \mathcal{A}(s=0)
+
\frac{(ih)^2}{2}\mathcal{A}(s=0)^2
+
\mathcal{O}(h^3)
\,,
```
where $`\mathcal{A}(s)=\mathcal{A}[(\frac{1}{2} - s)\vec{r}_i + (\frac{1}{2} + s)\vec{r}_j]`$. The second line indicates the midpoint rule,
found using $`\mathcal{A}(s)\simeq\mathcal{A}(\frac{1}{2}) + (s-\frac{1}{2})\mathcal{A}'(\frac{1}{2})+\ldots`$
and observing that and $`\frac{d^n}{ds^n}\mathcal{A}(s) = \mathcal{O}(h^n)`$.
where $`\mathcal{A}(s)=\mathcal{A}[(\frac{1}{2} - s)\vec{r}_i + (\frac{1}{2} + s)\vec{r}_j]`$.
As well known in lattice QCD, the field strength can be expressed in
terms of the link matrices $`U`$ via a plaquette loop. Consider then
......@@ -202,24 +190,16 @@ We can also calculate the matrix current $j\mapsto{}i$ between neighboring cells
J_{ij}^a
=
\frac{\partial}{\partial\xi}
S[
U_{ij}
\mapsto
e^{i\xi h T^a} U_{ij}
]\rvert_{\xi=0}
=
\frac{\partial}{\partial\xi}
S[
U_{ij}
\mapsto
U_{ij}
+
\frac{ih}{2}T^a U_{ij}\xi
T^a U_{ij}\xi
]\rvert_{\xi=0}
```
%
where $`T^a`$ is an appropriate matrix generator, and the transformation
is inserted only to one of the links.
is inserted to only one of the links.
The local gauge invariance now implies that there is an exact discrete
continuity equation
......@@ -227,10 +207,10 @@ continuity equation
\sum_{j\in{}N_i} J_{ij}^a
=
\frac{\partial}{\partial\xi}
S[Q(i)\mapsto{}e^{i\xi T^a}Q(i)e^{-i\xi T^a}]\rvert_{\xi=0}
S[Q(i)\mapsto{}e^{\xi T^a}Q(i)e^{-\xi T^a}]\rvert_{\xi=0}
=
\frac{\partial}{\partial\xi}
S[\Omega(i)\mapsto{}e^{-i\xi T^a}\Omega(i)e^{i\xi T^a}]\rvert_{\xi=0}
S[\Omega(i)\mapsto{}e^{-\xi T^a}\Omega(i)e^{\xi T^a}]\rvert_{\xi=0}
=
R_{i}^a
\,.
......@@ -238,19 +218,17 @@ continuity equation
This is one main advantage of the procedure, in addition to its
invariance vs. gauge fixing.
However, the definition of the matrix current is \emph{asymmetric}, so
However, the definition of the matrix current is *asymmetric*, so
that $`J_{ij}\ne{}-J_{ji}`$ as they differ by a quantity of order
$`\mathcal{O}(h^2)`$. The asymmetry arises when $`T^a`$ does not commute
with $`U_{ij}`$, so it is an issue only for the SU(2) component. The
problem is to some degree just in the interpretation of what $`J_{ij}`$
means:
problem is only in the interpretation.
It is the incoming current measured at site $`i`$, whereas
$`J_{ji}`$ is measured as site $`j`$. Since the parallel transport of
spin between these two locations can imply rotation due to the gauge
field, there's no reason why we should have $`J_{ij}=-J_{ji}`$, except
in the continuum limit where the two points become close to each
other.
The currents measured at sites $`i`$ and $`j`$ are different: since
the parallel transport of spin between these two locations can imply
rotation due to the gauge field, there's no reason why we should have
$`J_{ij}=-J_{ji}`$, except in the continuum limit where the two points
become close to each other.
## Implementation
......
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