From ec0807abd7738788884f8e129bdd8290caa325c0 Mon Sep 17 00:00:00 2001 From: Pauli Virtanen <pauli.t.virtanen@jyu.fi> Date: Mon, 29 Aug 2022 16:16:02 +0300 Subject: [PATCH] DOC --- doc/discretization.md | 54 +++++++++++++------------------------------ 1 file changed, 16 insertions(+), 38 deletions(-) diff --git a/doc/discretization.md b/doc/discretization.md index 8f171ed..5b4f913 100644 --- a/doc/discretization.md +++ b/doc/discretization.md @@ -8,11 +8,12 @@ in the action formulation. The action is ```math - S[Q] = \mathrm{Tr}[D(\hat{\nabla}Q)^2 + F_{ij}Q\hat{\nabla}_iQ\hat{\nabla}_jQ + \Omega Q] + S[Q] = \frac{i\pi\nu}{8} \mathrm{Tr}[D(\hat{\nabla}Q)^2 + \alpha F_{ij}Q\hat{\nabla}_iQ\hat{\nabla}_jQ + 4 i \Omega Q] \,, ``` -where $`\hat{\nabla}_j Q = \partial_j Q - i[\mathcal{A}_j, Q]`$. We'd -like the discretized functional to be also gauge invariant. +where $`\hat{\nabla}_j Q = \partial_j Q - i[\mathcal{A}_j, Q]`$ +and $\Omega = \epsilon\tau_3 + i\Delta$, $\Delta^\dagger = \Delta$. +We'd like the discretized functional to be also gauge invariant. We subdivide the space to cells, centered on a rectangular lattice $`\vec{r}_j=(h j_x, h j_y, h j_z)`$ with $`j_{x,y,z}\in\mathbb{Z}`$ @@ -49,7 +50,6 @@ the symmetry. ## Derivative term We then discretize -% ```math S_2 = @@ -78,19 +78,7 @@ U_{ji} = \sum_{n=0}^\infty i^n |\vec{r}_i-\vec{r}_j|^n \int_{-1/2}^{1/2}ds_1\int_{-1/2}^{s_1}ds_2\ldots\int_{-1/2}^{s_{n-1}}ds_n\, \mathcal{A}(s_1)\cdots\mathcal{A}(s_n) ``` -```math -U_{ji} -\approx - 1 + i h \mathcal{A}(s=0) - + - \frac{(ih)^2}{2}\mathcal{A}(s=0)^2 - + - \mathcal{O}(h^3) - \,, -``` -where $`\mathcal{A}(s)=\mathcal{A}[(\frac{1}{2} - s)\vec{r}_i + (\frac{1}{2} + s)\vec{r}_j]`$. The second line indicates the midpoint rule, -found using $`\mathcal{A}(s)\simeq\mathcal{A}(\frac{1}{2}) + (s-\frac{1}{2})\mathcal{A}'(\frac{1}{2})+\ldots`$ -and observing that and $`\frac{d^n}{ds^n}\mathcal{A}(s) = \mathcal{O}(h^n)`$. +where $`\mathcal{A}(s)=\mathcal{A}[(\frac{1}{2} - s)\vec{r}_i + (\frac{1}{2} + s)\vec{r}_j]`$. As well known in lattice QCD, the field strength can be expressed in terms of the link matrices $`U`$ via a plaquette loop. Consider then @@ -202,24 +190,16 @@ We can also calculate the matrix current $j\mapsto{}i$ between neighboring cells J_{ij}^a = \frac{\partial}{\partial\xi} - S[ - U_{ij} - \mapsto - e^{i\xi h T^a} U_{ij} - ]\rvert_{\xi=0} - = - \frac{\partial}{\partial\xi} S[ U_{ij} \mapsto U_{ij} + - \frac{ih}{2}T^a U_{ij}\xi + T^a U_{ij}\xi ]\rvert_{\xi=0} ``` -% where $`T^a`$ is an appropriate matrix generator, and the transformation -is inserted only to one of the links. +is inserted to only one of the links. The local gauge invariance now implies that there is an exact discrete continuity equation @@ -227,10 +207,10 @@ continuity equation \sum_{j\in{}N_i} J_{ij}^a = \frac{\partial}{\partial\xi} - S[Q(i)\mapsto{}e^{i\xi T^a}Q(i)e^{-i\xi T^a}]\rvert_{\xi=0} + S[Q(i)\mapsto{}e^{\xi T^a}Q(i)e^{-\xi T^a}]\rvert_{\xi=0} = \frac{\partial}{\partial\xi} - S[\Omega(i)\mapsto{}e^{-i\xi T^a}\Omega(i)e^{i\xi T^a}]\rvert_{\xi=0} + S[\Omega(i)\mapsto{}e^{-\xi T^a}\Omega(i)e^{\xi T^a}]\rvert_{\xi=0} = R_{i}^a \,. @@ -238,19 +218,17 @@ continuity equation This is one main advantage of the procedure, in addition to its invariance vs. gauge fixing. -However, the definition of the matrix current is \emph{asymmetric}, so +However, the definition of the matrix current is *asymmetric*, so that $`J_{ij}\ne{}-J_{ji}`$ as they differ by a quantity of order $`\mathcal{O}(h^2)`$. The asymmetry arises when $`T^a`$ does not commute with $`U_{ij}`$, so it is an issue only for the SU(2) component. The -problem is to some degree just in the interpretation of what $`J_{ij}`$ -means: +problem is only in the interpretation. -It is the incoming current measured at site $`i`$, whereas -$`J_{ji}`$ is measured as site $`j`$. Since the parallel transport of -spin between these two locations can imply rotation due to the gauge -field, there's no reason why we should have $`J_{ij}=-J_{ji}`$, except -in the continuum limit where the two points become close to each -other. +The currents measured at sites $`i`$ and $`j`$ are different: since +the parallel transport of spin between these two locations can imply +rotation due to the gauge field, there's no reason why we should have +$`J_{ij}=-J_{ji}`$, except in the continuum limit where the two points +become close to each other. ## Implementation -- GitLab